AIME2024實驗結(jié)果對比：

MATH-500實驗結(jié)果對比：

GPQA Diamond實驗結(jié)果對比：

LiveCodeBench V2實驗結(jié)果對比：

模型

訓(xùn)練數(shù)據(jù)量

AIME2024

MATH-500

GPQA Diamond

LiveCodeBench V2

DeepSeek-R1-Distill-Qwen-7B (reported)

800k

55.5

92.8

49.1

-

Bespoke-Stratos-7B (reported)

17k

20.0

82.0

37.8

36.1

OpenThinker-7B (reported)

114k

31.3

83.0

42.4

39.9

DistilQwen2.5-R1-7B

105k

43.33

88.4

42.93

46.38

模型

訓(xùn)練數(shù)據(jù)量

AIME2024

MATH-500

GPQA Diamond

LiveCodeBench V2

DeepSeek-R1-Distill-Qwen-32B (reported)

800k

72.6

94.3

62.1

-

Sky-T1-32B-Preview (reported)

17k

43.3

86.4

56.8

-

OpenThinker-32B (reported)

114k

66.0

90.6

61.6

68.9

DistilQwen2.5-R1-32B

105k

70.0

93.8

62.12

65.95

問題

Peter has $70 and wishes to spend an equal amount each day for one week. From Sunday through Wednesday, he spent his money on wooden action figures which cost $5 each. For the rest of the week, he will buy plastic action figures which cost $2 each. How many total action figures will he have by the end of the week?

答案

There are 7 days in a week so if he wishes to spend an equal amount of $70 each day that would be $70/7 = $<<70/7=10>>10\nFor four days (Sunday through Wednesday) he will spend 4*$10 = $<<4*10=40>>40\nHe will spend $40 on wooden action figures of $5 each which gives $40/$5 = <<40/5=8>>8 wooden action figures\nFor the remaining 3 days he will spend 3*$10 = $<<3*10=30>>30\nHe will spend $30 on plastic action figures of $2 each which gives $30/$2 = <<30/2=15>>15 plastic action figures\nAltogether, he will have 8+15 = <<8+15=23>>23 action figures.\n#### 23

DistilQwen2.5-R1-7B

<|begin_of_thought|>

Okay, let's try to figure out how many action figures Peter can buy. First, I need to understand the problem step by step.

So, Peter has $70 and wants to spend an equal amount each day for one week. That means seven days total. From Sunday through Wednesday, he spends money on wooden action figures that cost $5 each. Then, for the rest of the week (which would be Thursday and Friday, I guess, since the week ends on Saturday or Sunday?), he buys plastic ones that cost $2 each. The question is asking how many total action figures he'll have by the end of the week.

Wait, the problem says "from Sunday through Wednesday," so that's four days. Then "for the rest of the week," which would be Thursday and Friday, making two days. So total days: 4 + 2 = 6 days? Wait, a week is seven days. If he's spending from Sunday through Wednesday (4 days), then the rest would be Thursday and Friday (2 days), but that's only 6 days. Wait, maybe the "rest of the week" includes Saturday as well? Because Sunday to Wednesday is four days, then Thursday to Saturday would be three days left. Hmm, maybe I need to clarify that.

Wait, the problem says "for the rest of the week," which could be interpreted differently. Let me check again. The problem states: "From Sunday through Wednesday, he spent his money on wooden action figures..." So that's four days. Then "For the rest of the week, he will buy plastic action figures which cost $2 each." So "rest of the week" would be the remaining days of the week after Sunday through Wednesday. Since Sunday is the first day, the week would be Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, Saturday. So from Sunday to Wednesday is four days. The rest would be Thursday, Friday, Saturday. That's three days. So total days: 4 + 3 = 7 days, which is a week. Okay, so that makes sense.

So he spends four days on wooden figures ($5 each) and three days on plastic ones ($2 each). The total amount he spends is $70, and he wants to spend an equal amount each day. So first, we need to figure out how much he spends each day, then calculate how many action figures he can buy each day, and sum them up.

Wait, but the problem says he has $70 and wishes to spend an equal amount each day for one week. So the total amount he spends is $70, divided equally over seven days. So each day he spends $70 / 7 = $10 per day. So $10 per day total for the week.

But then, from Sunday through Wednesday (four days), he spends on wooden figures ($5 each), and the remaining three days (Thursday, Friday, Saturday) he spends on plastic figures ($2 each). So the total amount he spends on wooden figures is 4 days * $10/day = $40. Then the remaining amount is $70 - $40 = $30, which he spends over three days at $2 each. So $30 / 3 days = $10 per day, which matches the total daily spending of $10. So that checks out.

Now, how many wooden action figures does he buy? Each costs $5, and he spends $10 on them each day for four days. Wait, but if each day he spends $10 on wooden figures, then each day he can buy $10 / $5 = 2 action figures per day. So over four days, that's 2 * 4 = 8 wooden action figures.

Then, for the plastic figures, he spends $10 per day for three days. Each plastic figure is $2, so per day he can buy $10 / $2 = 5 action figures per day. Over three days, that's 5 * 3 = 15 plastic action figures.

Total action figures: 8 + 15 = 23.

Wait, but let me verify this again. Let's check the total money spent. Wooden: 8 figures * $5 = $40. Plastic: 15 figures * $2 = $30. Total: $40 + $30 = $70. Which matches the total he has. So that's correct.

Alternatively, another way to look at it: since he spends $10 each day, total $70 over 7 days. So each day he spends $10. For the first four days, he uses $10 each day on $5 action figures. So each day, $10 / $5 = 2 per day. 4 days: 8. Then the remaining three days, $10 each day on $2 action figures: $10 / $2 = 5 per day. 3 days: 15. Total 23.

Yes, that seems to be the answer.

<|end_of_thought|>

<|begin_of_solution|>

Peter has $70 to spend over 7 days. He spends $10 each day ($70 ÷ 7 = $10/day).

**Wooden action figures (Sunday–Wednesday, 4 days):**

Each costs $5. Daily purchase: $10 ÷ $5 = 2 figures/day.

Total: 2 × 4 = **8 figures**.

**Plastic action figures (Thursday–Saturday, 3 days):**

Each costs $2. Daily purchase: $10 ÷ $2 = 5 figures/day.

Total: 5 × 3 = **15 figures**.

**Total action figures:**

8 (wooden) + 15 (plastic) = **23**.

\boxed{23}

<|end_of_solution|>

DeepSeek-R1-Distill-Qwen-7B

<think>

Okay, let's see. Peter has $70 and wants to spend an equal amount each day for one week. So first, I need to figure out how much he spends each day. A week has seven days, right? From Sunday through Wednesday, he buys wooden action figures that cost $5 each. Then, for the rest of the week, which would be Thursday and Friday, he buys plastic ones that cost $2 each. The question is asking how many total action figures he'll have by the end of the week.

Wait, hold on. Wait, a week is seven days. Sunday through Wednesday is four days, and then the rest is Thursday and Friday, that's two days. So total of six days? Wait, Sunday, Monday, Tuesday, Wednesday is four days. Then Thursday and Friday, that's two days. So total of six days he's spending money, leaving Saturday out? The problem says "for one week," so maybe he starts on Sunday and goes through Saturday? But the problem mentions spending from Sunday through Wednesday, and then the rest of the week. Hmm.

Wait, the problem says: "From Sunday through Wednesday, he spent his money on wooden action figures which cost $5 each. For the rest of the week, he will buy plastic action figures which cost $2 each." So Sunday to Wednesday is four days, then the rest of the week would be Thursday to Saturday, which is three days. Wait, that's three days. So total of seven days? Wait, no. Sunday to Saturday is a week. If Sunday through Wednesday is four days, then the remaining days are Thursday, Friday, Saturday, which is three days. So total of seven days. So he spends money on four days buying wooden figures and three days buying plastic ones.

But the problem says he spends an equal amount each day for one week. So total spending per day is consistent. So first, I need to find out how much he spends each day. Let me denote the daily amount as x dollars. So total spending for the week would be 7x because it's one week. But he has $70. So 7x = $70. Therefore, x = 10. So he spends $10 each day.

Wait, but that seems high. Let me check. If he spends $10 each day for seven days, that's $70 total. That makes sense. So each day he spends $10. Then, from Sunday through Wednesday, which is four days, he spends 4 days * $10/day = $40 on wooden action figures. Then, for the rest of the week, which is three days (Thursday, Friday, Saturday), he spends 3 days * $10/day = $30 on plastic action figures. So total $40 + $30 = $70, which matches his total money. That checks out.

Now, the problem is asking for the total number of action figures he will have by the end of the week. So we need to calculate how many wooden figures he bought during the four days and how many plastic figures he bought during the three days, then sum them up.

First, wooden action figures cost $5 each. He spent $40 on them. So the number of wooden figures is $40 divided by $5 per figure. That's 40 / 5 = 8 figures.

Then, plastic action figures cost $2 each. He spent $30 on them. So the number of plastic figures is $30 divided by $2 per figure. That's 30 / 2 = 15 figures.

Adding them together: 8 wooden + 15 plastic = 23 total action figures.

Wait a second, but let me verify again to make sure I didn't make a mistake. So total days are seven. He spends $10 each day. Total $70. From Sunday to Wednesday: four days. 4 days * $10 = $40. Then Thursday, Friday, Saturday: three days * $10 = $30. Correct. Then wooden figures: $40 / $5 = 8. Plastic: $30 / $2 = 15. Total 23. That seems right.

But wait, the problem says "for the rest of the week, he will buy plastic action figures which cost $2 each." So does "rest of the week" mean the remaining days after Sunday through Wednesday? Sunday through Wednesday is four days, so the remaining three days would be Thursday, Friday, Saturday. So three days. So three days of $10 each day, totaling $30. Correct.

Therefore, the total number of action figures is 8 + 15 = 23. So the answer is 23.

</think>

Peter spends $10 each day for 7 days, totaling $70. From Sunday to Wednesday (4 days), he buys wooden action figures at $5 each:

\[

\frac{4 \text{ days} \times \$10}{\$5/\text{figure}} = \frac{\$40}{\$5} = 8 \text{ figures}.

\]

For the remaining 3 days (Thursday to Saturday), he buys plastic action figures at $2 each:

\[

\frac{3 \text{ days} \times \$10}{\$2/\text{figure}} = \frac{\$30}{\$2} = 15 \text{ figures}.

\]

Total action figures:

\[

8 + 15 = \boxed{23}.

\]

問題

A shoe store was having a weekend sale on a brand of popular tennis shoes. On Friday the store sold 14 pairs of tennis shoes. The next day they sold double that number of shoes. On the last day of the sale they sold one-half the amount that they did the day before, but six people returned their pairs because they didn't fit. How many pairs of tennis shoes were sold by the end of the sale?

答案

On Saturday 14*2=<<14*2=28>>28 shoes were sold\nOn Sunday 28/2=<<28/2=14>>14 shoes were sold\nBefore the returns were made 14+28+14=<<14+28+14=56>>56 pairs of shoes were sold\nAfter the returns were made 56-6=<<56-6=50>>50 pairs of shoe were sold\n#### 50

DistilQwen2.5-R1-32B 回復(fù)

<|begin_of_thought|>

Okay, let me try to figure out this problem step by step. So, the shoe store had a sale on tennis shoes over the weekend. Let's break down the information given.

First, on Friday, they sold 14 pairs of tennis shoes. That's straightforward. Then, the next day, which would be Saturday, they sold double that number. Double of 14 is 28, right? So, 28 pairs on Saturday.

Then, on the last day of the sale, which is Sunday, they sold half the amount they did the day before. The day before Sunday is Saturday, so half of 28 is 14. So, 14 pairs on Sunday. But wait, there's a catch here. Six people returned their pairs because the shoes didn't fit. So, we need to subtract those 6 returned pairs from the Sunday sales. That means instead of 14, they effectively sold 14 minus 6, which is 8 pairs on Sunday.

Now, to find the total number of tennis shoes sold by the end of the sale, we need to add up the sales from Friday, Saturday, and Sunday, taking into account the returns on Sunday.

So, Friday: 14 pairs.

Saturday: 28 pairs.

Sunday: 14 - 6 = 8 pairs.

Adding those together: 14 + 28 + 8.

Let me calculate that. 14 plus 28 is 42, and then 42 plus 8 is 50. So, total pairs sold would be 50.

Wait, but let me double-check to make sure I didn't make a mistake. Let's verify each step again.

Friday: 14 pairs. Correct. Saturday is double, so 14*2=28. Correct. Sunday is half of Saturday's sales, which is 28/2=14. But then subtract the 6 returned pairs. So 14-6=8. Then total is 14+28+8=50. Yeah, that seems right.

Hmm, another way to look at it: Total sold without returns would be 14 + 28 +14 = 56. Then subtract the 6 returned pairs, which would be 56 -6=50. Same result. So, that confirms it.

I think that's all. So the final answer should be 50 pairs of tennis shoes sold.

<|end_of_thought|>

<|begin_of_solution|>

The shoe store sold 14 pairs on Friday. On Saturday, they sold double that number, which is \(14 \times 2 = 28\) pairs. On Sunday, they sold half of Saturday's sales, which is \(28 \div 2 = 14\) pairs, but then subtract the 6 pairs returned. Therefore, the effective sales on Sunday are \(14 - 6 = 8\) pairs.

Adding up the sales from all three days:

\(14\) (Friday) + \(28\) (Saturday) + \(8\) (Sunday) = \(14 + 28 + 8 = 50\).

The final answer is \(\boxed{50}\).

<|end_of_solution|>

DeepSeek-R1-Distill-Qwen-32B 回復(fù)

<think>

Okay, let's try to figure out how many tennis shoes were sold by the end of the sale. So, the problem is about a shoe store that had a weekend sale. I'll need to break it down day by day to make sure I understand each part correctly.

First, on Friday, the store sold 14 pairs of tennis shoes. That seems straightforward. So, Friday sales are 14 pairs.

Next, the problem says that on the next day, which would be Saturday, they sold double that number. Hmm, double of Friday's sales. So, double of 14 is 14 times 2. Let me calculate that: 14 * 2 = 28. So, they sold 28 pairs on Saturday.

Now, moving on to the last day of the sale, which is Sunday. The problem states that on Sunday, they sold half the amount they did the day before. The day before Sunday is Saturday, so half of Saturday's sales. Saturday was 28 pairs, so half of that would be 28 / 2. Let me do that math: 28 divided by 2 is 14. So, they sold 14 pairs on Sunday before any returns.

But wait, the problem mentions that six people returned their pairs because they didn't fit. So, we need to subtract those returns from Sunday's sales. So, Sunday's total after returns would be 14 minus 6. Let me calculate that: 14 - 6 = 8. So, they effectively sold 8 pairs on Sunday after the returns.

Now, to find the total number of pairs sold by the end of the sale, I need to add up the sales from each day. That would be Friday's 14, plus Saturday's 28, plus Sunday's 8. Let me add them up step by step.

First, 14 (Friday) + 28 (Saturday) = 42. Then, adding Sunday's 8 to that: 42 + 8 = 50.

Wait, does that make sense? Let me double-check each step to make sure I didn't make a mistake. Friday was 14, Saturday was 28, Sunday was 14 before returns, which became 8 after subtracting 6. So, 14 + 28 is indeed 42, and 42 + 8 is 50. Yeah, that seems correct.

But just to be thorough, maybe I should think about whether the returns affect the total sold or just the net sales. The problem says "they sold one-half the amount that they did the day before, but six people returned their pairs." So, I think the six returns are subtracted from Sunday's sales, so the total sold would be the initial sales minus the returns. Therefore, the calculation I did is correct.

So, adding all three days together: 14 + 28 + (14 - 6) = 14 + 28 + 8 = 50. Yep, that looks right.

</think>

The total number of pairs sold by the end of the sale is 50.

The final answer is 50.